INDIAN CREEK (SHACKELFORD COUNTY)
INDIAN CREEK (Shackelford County). Indian Creek rises seven miles south of Albany in south central Shackelford County (at 32°37' N, 99°19' W) and runs east for ten miles to its mouth on Hubbard Creek, just southwest of McCathrine Mountain and east of State Highway 6 (at 32°39' N, 99°12' W). The creek begins in rolling hills surfaced by clay and sandy loam that supports scrub brush, mesquite, cacti, and grasses. Later in its course it traverses flat terrain with local shallow depressions, surfaced by clay and sandy loam that supports water-tolerant hardwoods, conifers, and grasses.
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The following, adapted from the Chicago Manual of Style, 15th edition, is the preferred citation for this article.Handbook of Texas Online, "Indian Creek (Shackelford County)," accessed January 17, 2017, http://www.tshaonline.org/handbook/online/articles/rbi21.
Uploaded on June 15, 2010. Published by the Texas State Historical Association.