INDIAN CREEK (SHACKELFORD COUNTY)
INDIAN CREEK (Shackelford County). Indian Creek rises seven miles south of Albany in south central Shackelford County (at 32°37' N, 99°19' W) and runs east for ten miles to its mouth on Hubbard Creek, just southwest of McCathrine Mountain and east of State Highway 6 (at 32°39' N, 99°12' W). The creek begins in rolling hills surfaced by clay and sandy loam that supports scrub brush, mesquite, cacti, and grasses. Later in its course it traverses flat terrain with local shallow depressions, surfaced by clay and sandy loam that supports water-tolerant hardwoods, conifers, and grasses.
Image Use Disclaimer
All copyrighted materials included within the Handbook of Texas Online are in accordance with Title 17 U.S.C. Section 107 related to Copyright and “Fair Use” for Non-Profit educational institutions, which permits the Texas State Historical Association (TSHA), to utilize copyrighted materials to further scholarship, education, and inform the public. The TSHA makes every effort to conform to the principles of fair use and to comply with copyright law.
For more information go to: http://www.law.cornell.edu/uscode/17/107.shtml
If you wish to use copyrighted material from this site for purposes of your own that go beyond fair use, you must obtain permission from the copyright owner.
The following, adapted from the Chicago Manual of Style, 15th edition, is the preferred citation for this article.Handbook of Texas Online, "Indian Creek (Shackelford County)," accessed June 26, 2016, http://www.tshaonline.org/handbook/online/articles/rbi21.
Uploaded on June 15, 2010. Published by the Texas State Historical Association.