INDIAN KNOB. Indian Knob rises 1,350 feet above sea level at a point about four miles west of Springtown in northern Parker County (at 32°57' N, 97°74' W). The surrounding terrain is flat to rolling with local escarpments and is surfaced by mostly deep, fine sandy loams that support brush and grasses.
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The following, adapted from the Chicago Manual of Style, 15th edition, is the preferred citation for this article.Handbook of Texas Online, "Indian Knob," accessed February 22, 2017, http://www.tshaonline.org/handbook/online/articles/rji03.
Uploaded on June 15, 2010. Published by the Texas State Historical Association.